列表解析中的第一个表达式可以是任何表达式,包括列表解析。

考虑下面由三个长度为 4 的列表组成的 3x4 矩阵:

1
2
3
4
5
>>> matrix = [
... [1, 2, 3, 4],
... [5, 6, 7, 8],
... [9, 10, 11, 12],
... ]

现在,如果你想交换行和列,可以用嵌套的列表推导式:

1
2
>>> [[row[i] for row in matrix] for i in range(4)]
[[1, 5, 9], [2, 6, 10], [3, 7, 11], [4, 8, 12]]

像前面看到的,嵌套的列表推导式是对 for 后面的内容进行求值,所以上例就等价于:

1
2
3
4
5
6
>>> transposed = []
>>> for i in range(4):
... transposed.append([row[i] for row in matrix])
...
>>> transposed
[[1, 5, 9], [2, 6, 10], [3, 7, 11], [4, 8, 12]]

反过来说,如下也是一样的:

1
2
3
4
5
6
7
8
9
10
>>> transposed = []
>>> for i in range(4):
... # the following 3 lines implement the nested listcomp
... transposed_row = []
... for row in matrix:
... transposed_row.append(row[i])
... transposed.append(transposed_row)
...
>>> transposed
[[1, 5, 9], [2, 6, 10], [3, 7, 11], [4, 8, 12]]

在实际中,使用内置函数组成复杂流程语句。对此种情况zip()函数将会做的更好:

1
2
>>> list(zip(*matrix))
[(1, 5, 9), (2, 6, 10), (3, 7, 11), (4, 8, 12)]